๐Ÿ“š SAT Practice
Advanced Math

SAT polynomials: read zeros, factors, and turning points from a graph

Every x-intercept of a polynomial is a factor in disguise. Learn to move between factors, zeros, and graphs, spot where a graph bounces instead of crossing, and use the remainder theorem shortcut.

SPSAT Practice Editorial8 min read

The short version

What you'll take away

  • If p(a) = 0, then (x โˆ’ a) is a factor of p(x), and the graph crosses or touches the x-axis at x = a.
  • A factor that appears an even number of times makes the graph touch the axis and turn back; an odd number makes it cross.
  • The remainder when p(x) is divided by x โˆ’ a equals p(a).
In this article

Factors, zeros, and x-intercepts are the same information

Consider \(\displaystyle p(x) = (x + 2)(x - 1)(x - 3)\). A product is zero when one of its factors is zero, so \(\displaystyle p(x) = 0\) when \(\displaystyle x = -2\), \(\displaystyle x = 1\), or \(\displaystyle x = 3\). Those zeros are exactly where the graph meets the x-axis.
The y-intercept comes from substituting \(\displaystyle x = 0\): \(\displaystyle p(0) = (2)(-1)(-3) = 6\).

The study lab

y = (x + 2)(x โˆ’ 1)(x โˆ’ 3)

A cubic polynomial with three zeros and a y-intercept of 6.

What to notice: Each factor (x โˆ’ a) produces a zero at x = a. Reading the graph backward, the intercepts tell you the factors.

Touch or cross: multiplicity

If a factor repeats, its zero has a higher multiplicity. In \(\displaystyle y = (x + 2)(x - 1)^2\), the factor \(\displaystyle x - 1\) appears twice. At \(\displaystyle x = 1\), the graph touches the axis and turns back instead of crossing it. At \(\displaystyle x = -2\), where the factor appears once, it crosses.

The study lab

y = (x + 2)(x โˆ’ 1)ยฒ

A single zero at โˆ’2 (crosses) and a double zero at 1 (touches).

What to notice: Odd multiplicity: the sign of y changes, so the graph crosses. Even multiplicity: the sign stays the same, so the graph bounces.

The remainder theorem shortcut

When a polynomial \(\displaystyle p(x)\) is divided by \(\displaystyle x - a\), the remainder is \(\displaystyle p(a)\). So โ€œp(x) divided by x โˆ’ 2 leaves a remainder of 7โ€ means \(\displaystyle p(2) = 7\). A remainder of 0 means \(\displaystyle x - a\) is a factor.
The SAT often asks which expression must be a factor given a value, or which value is a zero given a factor. Translate between them with the sign flip: zero at \(\displaystyle -4\) means a factor of \(\displaystyle x + 4\).

Your turn

Quick practice

For a polynomial p, p(โˆ’4) = 0. Which of the following must be a factor of p(x)?

Hint: Write the factor as x โˆ’ a with a = โˆ’4.

Choose one answer

Practice: try these before checking the answers

Factor first whenever you can.
  • 1. What are the zeros of \(\displaystyle p(x) = x(x - 5)(x + 1)\)?
  • 2. Factor \(\displaystyle x^3 - 4x\) and find its zeros.
  • 3. If \(\displaystyle p(3) = 0\), name a factor of \(\displaystyle p(x)\).
  • 4. When p(x) is divided by x + 1, the remainder is 4. What is p(โˆ’1)?
  • 5. Where does \(\displaystyle y = (x - 2)^2(x + 1)\) touch the x-axis, and where does it cross?

Sources & further reading

One step from here

Put the idea to work.

SAT Practice helps you turn questions into useful feedback, so each session has a next step.

Try a practice set